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help1402

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UWA week 35 (2nd semester, week 6) ↓

worksheet 2 - question 3 - having (all 4)

3:43pm Tue 27th Aug, ANONYMOUS

Hi,

>From the lectures,

"Column names in HAVING clause must also appear in the GROUP BY list or be contained within an aggregate function." The solution uses HAVING count(cust_id) > 2 and city OR phone IS NOT NULL However, column city, phone are not in the GROUP BY list. Could someone please explain why? Thanks.

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