so if the RAM has page numbers 0-7 from processes 0 and 1 all initially time step 0, and the disc has processes 2-3, and we receive the instruction '0' there is nothing to move in from the disc as all of process 0 is in RAM. We need to evict the first page loaded (page 0 in process 0 in RAM slot index 0) and gets moved into the disc now there are 7 slots loaded into the RAM and 9 slots loaded in the disc so now there is a page in disc that can be loaded into RAM from process 0 (the page that was evicted from RAM) and this page now gets moved into the empty slot in the RAM so basically the only thing that changes is the time step of the first page when being evicted and selected (increases by 2) is this correct?