I recall that on my question on this thread (https://secure.csse.uwa.edu.au/run/help2002?p=np&opt=U308) it was proposed that we compile code without -Werror, but even if we just use -Wall it also throws all warnings, is that expected and fine? Here is example:

My sample translated code is: #include <stdio.h> int main(int argc, char *argv[]) { double x; x = 2.3; print 5; return 0; }

I am compiling this translated c code using "cc -std=c11 -Wall -o mycode mycode.c "

I am getting this warning error: warning: variable ‘x’ set but not used [-Wunused-but-set-variable] 6 | double x; | ^ 5

(Note that "5" is printed just fine)

"Samay Gupta" [email protected] wrote:

I recall that on my question on this thread (https://secure.csse.uwa.edu.au/run/help2002?p=np&opt=U308) it was proposed that we compile code without -Werror, but even if we just use -Wall it also throws all warnings, is that expected and fine? Here is example:

My sample translated code is: #include <stdio.h> int main(int argc, char *argv[]) { double x; x = 2.3; print 5; return 0; }

I am compiling this translated c code using "cc -std=c11 -Wall -o mycode mycode.c "

I am getting this warning error: warning: variable ‘x’ set but not used [-Wunused-but-set-variable] 6 | double x; | ^ 5

(Note that "5" is printed just fine)

Just multiply x by 1 in the code.

e.g. x = x*1; and the error/warning will go away.