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 UWA week 22 (1st semester, study break) ↓
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helpful
4:49pm Sun 2nd Jun, ANONYMOUS

a super simple simplification is that amortized = average for the first question of the second test it says A cyclist can travel 24 km/hour when wind is blowing from behind, and 12 km/hour against the wind. The cyclist travels A to B and then B to A. The wind is blowing from A to B throughout the travel of the cyclist. What is the amortized speed of the cyclist? to keep the calculations simple assume that the distance between A and B is 24 km. this means that the cyclist took 1 hour to go from A to B (24km/hr) but 2 hours to back (12km/hr). So the total time taken is 3 hours. And since the cyclist went from A to B then B to A he traveled 48km. 48km / 3 hours = 16 km/hr

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