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This forum is provided to promote discussion amongst students enrolled in CITS2200 Data Structures and Algorithms.

Please consider offering answers and suggestions to help other students! And if you fix a problem by following a suggestion here, it would be great if other interested students could see a short "Great, fixed it!"  followup message.

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 UWA week 22 (1st semester, study break) ↓
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helpful
12:11pm Sun 2nd Jun, ANONYMOUS

Having some trouble wrapping my head around this concept. Is there an equation that fits all solutions when we are looking for this type of analysis? Or do we have to derive one? Also, regarding Q1 of the second mid sem test, the question about amortized speed, I was wondering how we were supposed to go about calculating that? As the answers only tell us it's 16km/h but now why.


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4:49pm Sun 2nd Jun, ANONYMOUS

a super simple simplification is that amortized = average for the first question of the second test it says A cyclist can travel 24 km/hour when wind is blowing from behind, and 12 km/hour against the wind. The cyclist travels A to B and then B to A. The wind is blowing from A to B throughout the travel of the cyclist. What is the amortized speed of the cyclist? to keep the calculations simple assume that the distance between A and B is 24 km. this means that the cyclist took 1 hour to go from A to B (24km/hr) but 2 hours to back (12km/hr). So the total time taken is 3 hours. And since the cyclist went from A to B then B to A he traveled 48km. 48km / 3 hours = 16 km/hr


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7:17pm Sun 2nd Jun, ANONYMOUS

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