Hello, I was struggling with Hamming Code and I think I now have a good understanding of Hamming Correction but I just want to make sure it's correct. When we look at a codeword that has been encoded using the Hamming Code, it is a general rule that a parity bit will always be in the position that is a power of 2. Meaning that a parity bit is correlated to data bits that, when broken down into a sum of powers of 2, one of their addends is equal to that parity bit's position. This implies that we are working with the highest possible power of 2 downwards. For example, if we look at a data bit that is in position 10, the highest possible power of 2 that fits in 10 is 8. Then we are left with 2. So this data bit contributes to parity bits in positions 2 and 8. If the sender encoded using even parity, then the receiver must also check for errors in even parity. So if Parity Bit 1 is related to data bits 3, 5, 7, 9, 11, where, including the value of the parity bit, there is an odd number of 1's among these 6 values, that means that there is an error and c+=1 where 1 is the position of the parity bit. Then we work out the other parity bits in the same way. Is this correct?

Yes, all of that is correct. The calculations are the same for both odd and even partity (the choice just determines what the 'final' value of each checkbit will be, and both the sender and receiver must agree on which (odd/even) is being used.