You can if you want but it is unnecessary.

No.

Time increases by 1 every time you read a number from in.txt. See here https secure.csse.uwa.edu.au run help2002?p np opt B682 year 2024

ANONYMOUS wrote Honestly it could be interpreted either way, but I don't think you need to increase the last accessed time if you are ignoring the entry since it would presumably take no time to ignore an entry (as opposed to loading an entry onto RA...

One person submits for the team. Put both of your names and student numbers as comments at the top of the file.

It is definitely possible to complete the project without creating virtual memory, but I believe Amitava intends you to create virtual memory (since it is in the specification), so it is probably best to create virtual memory.

One person submits. You put your names and student numbers at the top of the file.

ANONYMOUS wrote No, it isn't. I don't think he intended for the example output to match the in.txt file.

ANONYMOUS wrote My other post was incorrect. Don't increase the time stamp when you ignore a page.

ANONYMOUS wrote You are right the time stamp shouldn't increase when you ignore a page I got mixed up with the reloading.

ANONYMOUS wrote As Anon said this is incorrect. The page table is the slot in RAM the page occupies. A slot is of size 2. So, it should be 0, 1, 2, 3 4, 7, 99, 99 99, 99, 5, 99 99, 99, 6, 99

I don't know. Hopefully before the exam.

As Anon said, either way is fine. It is not necessary to have a newline character at the end. np.

Yes. The first argument will always be in.txt (file read from) and the second will be out.txt (file written to).

Assumptions should appear as a comment at the top of your source file.

Not completely sure what you mean but you don't need to provide code for this question. Recall there are two types caching methods you can use that apply the principle of Locality of Reference and you can use two examples to demonstrate how they can ...

With this type of question, you would define and explain the Principle of Referential Locality, then create two scenarios (or examples) that demonstrate how it works and how the OS can use it to improve performance. Ultimately the question is testing ...

Since the size of the RAM, page table and Virtual memory is static, you can use static arrays.

Yes.

Answered here https secure.csse.uwa.edu.au run help2002?p np opt U685

Yep. They are both correct.

Both are correct. The struct you make doesn't need to be exactly the same.

ANONYMOUS wrote This isn't correct because we are using the "Local" Least Recently Used (LRU) algorithm to evict processes. You seem to be using "global". 1. At time 0,1,2,3 0 0 0 0 is loaded. 2. At time 4 The fifth zero is ignored. 3. At time 5,6,7,8...

ANONYMOUS wrote I believe that's a typo should be ". simulation.c in.txt out.txt".

ANONYMOUS wrote You wouldn't gain marks since it isn't asked for in the specification. Whether you lose marks or not would be up to the discretion of whoever marks your code (usually, you wouldn't be marked down for having extra code that exists for ...

Thanks. Your solution is correct.

ANONYMOUS wrote Just what is written in the spec. each page table entry on a new line. Followed by the RAM contents with each page semi-colon separated. You also need to explicitly print out the empty slots of RAM (You can just print "empty" for that...

ANONYMOUS wrote You have to take the page that has not been in the RAM before. So 3.

That's right.

Thanks for clarifying.

Yes. The spec explicitly states the names of the files will be in.txt and out.txt As Anon said it is good practice to be able to read a file of any name as opposed to a hard coded value. However, for this project you can assume that the file name pass...

Looks good.

ANONYMOUS wrote Last I heard marking is, unfortunately, going very slowly. Hopefully it will be done before the exam.

All good answered here https secure.csse.uwa.edu.au run help2002?p np opt U545 hl input 20validation

ANONYMOUS wrote Hi Anon That's fine. np.

The spec doesn't specify the exact format. You would need to ask Amitava to be complete sure.

Could you state exactly which part of the specification you are referring to? Or what it said exactly? I can't seem to find it. The spec states "The last accessed time of a page will be the time step when you brought the page to RAM. For example, aft...

Both seem correct.

Answered here https secure.csse.uwa.edu.au run help2002?p np opt U574

ANONYMOUS wrote Yes, Amitava said you can either do that or reload the pg 0 again (which would just be updating the "last accessed" variable). I believe moving pointers was the intention, otherwise using an array of pointers to structs wouldn't have a...

In general, if you are looking for resources for this unit look on LMS as Amitava can't upload anything on Chris's website.

ANONYMOUS wrote Yes. Is there a need to present it in stdout? No.

ANONYMOUS wrote Yes (although technically you could use an array of size 16 since there are duplicates).

ANONYMOUS wrote I don't think so, Amitava never said anything about an assumption sheet for this project. From his email he said to put any assumptions you made as comments in the file you submit. Make sure to put them at the top of the file.

ANONYMOUS wrote The specification states that the struct you use "may" look like the one it provides. So, no you don't have to use the exact same struct. However, I do believe you need to use a struct.

ANONYMOUS wrote Yes. Global means evict the page in RAM with the lowest "last accessed" time. Local means evict the page from the same process in RAM with the lowest "last accessed" time (e.g. If you are loading process 0 onto RAM and RAM is full and ...

ANONYMOUS wrote Amitava needs to clarify. I'm assuming you don't need a ";" at the end. If memory isn't allocated, then how are you able to store anything in your structure? Most likely, it's bad practice to not free dynamically allocated (or malloced)...

ANONYMOUS wrote Normally half the exam is a writing C code by hand but since Amitava is teaching the unit now that may not be the case. You would have to ask him.

ANONYMOUS wrote One person submits the simulation.c file with the names of both members in the file as a comment at the top.

ANONYMOUS wrote Yes. Yes. So the out.txt of the example above should look like this? For the RAM content is it process, page, time stamp; or page, process, time stamp; ? I believe it follows the same order as the struct, which is process;page;last acce...

ANONYMOUS wrote Yes. Yes. You need to remember the last page you loaded for each process. It's up to you how to determine how to do that. Since RAM is full and there is no page of process 3 on RAM, we can't use local LRU to make room, we need to use glo...

ANONYMOUS wrote If you are ignoring the input the time stamp wouldn't increase since you aren't loading it into RAM. I'm not sure how project 2 will be marked. You would have to ask Amitava to know for certain. Projects are usually automatically marke...

Yes, if you're assuming you can load the same process twice.

ANONYMOUS wrote Not sure, you would have to ask Amitava to know for sure. I don't think it will be larger than 10000 inputs. 0 1 2 3 99 99 99 99 99 99 99 99 99 99 99 99

Yes, Virtual Memory doesn't change. We are just moving pointers in and out of RAM (and updating the page table to keep record of where the pages are in RAM). np

Simulations are a model or abstraction of the "real world", they do not 100 match what is done in practice. How much a simulation matches the real world depends on the level of detail necessary (as per the specification). With all simulations you ne...

ANONYMOUS wrote Answered here https secure.csse.uwa.edu.au run help2002?p np opt U564 Their contents are not disjoint (e.g. for the example you gave, after the first-time step the pointer for page 0, process 0 will be in both RAM and Virtual Memory)...

There will be a maximum of 8 pages in RAM. It does make sense. You can identify a specific page by its process id and page number. Why will there need to be 2 different processes in RAM? Technically a page from each process can be in RAM. Unless you ar...

ANONYMOUS wrote It can be initialized sequentially. So long as the disk starts with all the process pages inside. So, 0-3 pages for each of the 0-3 processes. Yes, as the spec states if a page of a process isn't in RAM its entry in the page table is 9...

If you mean RAM is full and you are trying to load a new page onto RAM, so you need to use LRU algorithm to make room then yes. I mean the program will still output what it is meant to (it will still work) but I'm not sure if Amitava will be fond of t...

Occurs when RAM is full and you are trying to load a new page into memory. E.g. If page 0 of process zero is in memory and RAM is full and you are trying to load the next page of process 0, then you evict the least recently loaded page of process 0 (...

I meant to say "hello world" four times.

ANONYMOUS wrote Answered here https secure.csse.uwa.edu.au run help2002?p np opt U417

You have no idea what is in stdout when you call print. When you call print the buffer is "flushed" everything inside of it comes out. So, there no guarantee that the result will always be print 4 times. As the correct answer said "The form of out...

This is really hard to read and hard to know what question you are asking. I mean for one, your output doesn't print empty slots. It also doesn't print the same slot twice. The structure for some reason has 99 in it? 99 should only be used in the page...

RAM starts empty. You only load processes based on the file. At instruction 0, there is no process to evict. Since the RAM is empty. Amitava said a process can only be loaded once. So, the fifth 0 would be ignored. I think that was a mistake on Amitava...

ANONYMOUS wrote You would just ignore all lines except the first. However, best practice is to stop processing the file if you detect multiple lines since you would assume the file was corrupted.

ANONYMOUS wrote Depends on Amitava. I would guess, based on the specification that there wouldn't be a trailing ";", since its only purpose is to separate the locations.

ANONYMOUS wrote Cyclically, so it would be Page 3. Amitava said you can only load the process once, so there would be no next page. Yes.

Yes. Yes.

ANONYMOUS wrote If Amitava said to only do it once then follow what he said.

ANONYMOUS wrote That is the spec unless Amitava changes it. The output doesn't really "show" the default time anyway. Since you only print the times of pages that are loaded onto RAM.

ANONYMOUS wrote Yes. I believe you still have to print "Empty" unless Amitava clarifies. I wouldn't say so since the spec states to print the contents of RAM, which would include the empty slots.

ANONYMOUS wrote Hi, Amitava can't access the lab sheets on Chris's website. So, I'm not sure if there will be anymore lab sheets. If there are he will upload them to LMS.

ANONYMOUS wrote Answered here https secure.csse.uwa.edu.au run help2002?p np opt U545

Correct

Yep, that is correct.

Actually the best practice is to never call "exit" because it doesn't end the program "gracefully". The best practice is to return EXIT FAILURE (1) in main. If you are interested.

If you encountered a number outside of 0-3 then you would assume the file is corrupted and you shouldn't continue reading. So best practice is to print an error message then call exit(EXIT FAILURE).

If you countered a number outside of 0-3 then you would assume the file is corrupted and you shouldn't continue reading. So best practice is to print an error message then call exit(EXIT FAILURE).

Yes that seems right. just remember that Disk has all 16 pages in it (4 for each process) and disk is never changed. Also RAM has frames 0-7. Processes have pages 0-3.

I've answered this question here https secure.csse.uwa.edu.au run help2002?p np opt U516

You need to make your own tests and see if your program produces what you expect given the project specification. I've given one example here https secure.csse.uwa.edu.au run help2002?p np opt U525

I'll just change the output to avoid confusion. Shame there is no edit option on the forum 0 99 99 99 1 99 99 99 2 99 99 99 3 99 99 99 0,0,0;0,0,0;1,0,1;1,0,1;2,0,2;2,0,2;3,0,3;3,0,3;Empty;Empty;Empty;Empty;Empty;Empty;Empty;Empty;

I think this is meant to be a simple project. So, I don't think input sanitization is necessary, but it is good practice.

ANONYMOUS wrote It's going to take a while. Hopefully before the exam.

Isn't this your page table? process 1 0,1,2,3 process 2 4,5,6,7 process 3 99,99,99,99 process 4 99,99,99,99 It's hard to follow what you are doing to RAM and disk because it doesn't provide information as to which page of which process is in RAM. RAM ...

ANONYMOUS wrote See here https secure.csse.uwa.edu.au run help2002?p np opt U516 Gave an example of output here https secure.csse.uwa.edu.au run help2002?p np opt U525

When constructing your array of pointers to structures did you make sure to malloc memory to them before accessing their contents? Segfault means you are going out of bounds in memory. If malloc wasn't used the pointer points to nothing (no memory) s...

Are you asking if there are any pages in RAM when the simulation starts? The RAM is empty there are no pages in RAM.

I'm not sure what your question is about. Are you asking what happens if RAM is full and we are bringing in another process which isn't in RAM? In that case you would evict the page of any process with the lowest "last accessed" time. Also, not sure ...

ANONYMOUS wrote Also, I should mention the contents of RAM I did was incorrect. The first digit should represent the process and the second should represent the page but I accidently did it the wrong way around.

ANONYMOUS wrote There is a specific format. Pretty much the one I provided. Except for the empty sections of the RAM because it isn't specified in the spec what should be printed if RAM is empty. Amitava would have to clarify.

I forgot Amitava changed the spec, should be 0 99 99 99 1 99 99 99 2 99 99 99 3 99 99 99 0,0,0;0,0,0;0,1,1;0,1,1;0,2,2;0,2,2;0,3,3;0,3,3;0,0,0;0,0,0;0,0,0;0,0,0;0,0,0;0,0,0;0,0,0;0,0,0;

ANONYMOUS wrote The updated page table and RAM. 1 0 0 0 1 0 0 0 1 0 0 0 1 0 0 0 0,0,0;0,0,0;0,1,1;0,1,1;0,2,2;0,2,2;0,3,3;0,3,3;0,0,0;0,0,0;0,0,0;0,0,0;0,0,0;0,0,0;0,0,0;0,0,0; See here https secure.csse.uwa.edu.au run help2002?p np opt U515

ANONYMOUS wrote You should have 4 pages in RAM. I'm not sure if I understand your question but if you exceed the number of pages for a process you likely would need to evict the first loaded page for that process and replace it with the new process. I...

Hi Leran, I'm sorry but I think you need to make your own. You can use the example given in the project specification as a guide.

ANONYMOUS wrote Yes. That is always what is done when submitting group projects.

Each process has exactly 4 pages in VMEM which can be loaded to RAM. Memory of struct pointers. When you store the pointers in VMEM you are storing the structs there also. From the in.txt file you know the process to load onto RAM. You load the ne...

I C what you mean. I think it's a typo, I think it is just 4 processes. Otherwise, the size of virtual memory wouldn't be enough to store all the processes. To be certain Amitava would need to clarify.

ANONYMOUS wrote Hi, I assume so, since that's what the project sheet said. np.

ANONYMOUS wrote The project sheet states you "can" work as a group. So, I'm assuming that means it's fine if you work alone. Project is definitely small enough to do on your own.

ANONYMOUS wrote I would say so but to be 100 sure I recommend checking with Amitava.

ANONYMOUS wrote There are no stupid questions. Only stupid answers. I think either will be accepted since it wasn't specified if ml print statement will print a newline at the end or not. I think logically it would make more sense if ml did print a n...

ANONYMOUS wrote Do not make your code public until all the late submissions are in. Some people will have extensions and so they will still be doing their project.

ANONYMOUS wrote I don't think Amitava can modify the website. Only Chris can because it is his website. I'm guessing Amitava will place updated on LMS as needed.

ANONYMOUS wrote Doing your own research is fine so long as you use the approved c11 libraries (e.g. methods from string.h). I think a good rule of thumb is to only use the c libraries covered in labs and lectures.

I can't be 100 sure. If I had to guess it would have something to do with the compiler you are using. E.g. mac vs linux. gcc is more particular wants things done a certain why. I think clang is more lenient. Or in other words I think you are using d...

I don't think you completely understand how argument passing works in ml. Have you read these posts? https secure.csse.uwa.edu.au run help2002?p np opt U441 hl arg0 https secure.csse.uwa.edu.au run help2002?p np opt U344 hl arg0

Firstly, remember that you need to submit 1 c source file. So, you need to merge these files together. The error you are getting usually mean you are trying to compile an object file. In other words a file with the ".o" extension. Object files are us...

Wait ".o" is an object file not an executable. You aren't compiling it correctly.

Perhaps you're not using the right command to compile it? Is the command exactly the same as what you are writing to the terminal?

Are you compiling on Linux or mac? Do you mean manually compiling and running the file or do you mean manually just running the file?

Just make sure to convert argv 1 to a double.

Yes. That is the only thing you need to check. If you see a variable, you don't recognize you must replace it with 0.

Yea Amitava said you can do it anyway you want. So long as runml.c is compiled with -Wall, -Werror, etc.

Could be anything. Need more information. A common error is people don't pass the correct path to the file in execv or system. So, they try to compile a file that "doesn't exit" and so compilation fails.

You would have to ask Chris since he wrote the project, usually it is fine. However, you definitely can't share the solution to the project until all late submission are in.

This is a reasonable assumption. Make sure to put it in your assumption doc.

Amitava said you can do either. For unused variable multiply the variable by 1 and the error goes away.

ANONYMOUS wrote Usually, it's just one person. Amitava would have to clarify.

ANONYMOUS wrote This is not what Chris means. He means to not submit header files (e.g. you can't submit a header file you wrote). You still have to import header files or compilation will fail. Your code won't compile if you do this. This is what ...

ANONYMOUS wrote You can make assumptions about any of the project requirements that are unclear. In the doc you are stating what you believe you are meant to do or what you believe the requirements are telling you to do. E.g. one assumption could be ...

ANONYMOUS wrote No, I don't think so, since they represent the command line arguments. However, since it hasn't been clarified you can put whatever you assume in the doc.

Answered here https secure.csse.uwa.edu.au run help2002?p np opt U275 hl white 20space

ANONYMOUS wrote Possibly, but it is a bit ambiguous you could probably have an assumption in your assumption doc about it. This definitely has to be true. I believe the point 9 is stating that in the ml file the function definition has to come before t...

ANONYMOUS wrote Amitava said to use 'cc -std c11 -Wall -o output output.c'.

ANONYMOUS wrote Don't need to validate y 2 since it is an expression, but you do need to validate the assignment.

ANONYMOUS wrote Option d is wrong. You just had a lucky number choice where the result is the same. If you first divide by ten you perform integer division and so the result becomes 2409, modulo 100 gives 09, which is 9 in this case. A is correct. modu...

You don't need to do this. The arguments are "passed in" into the variables arg0, arg1, etc. This is what you are meant to do. np

ANONYMOUS wrote I believe Chris intended students to actually parse the strings themselves. If you want confirmation, you will have to ask Amitava. Honestly, I don't think regex.h will make your life easier.

ANONYMOUS wrote WSL stands for "Windows Subsystem for Linux". So Linux.

Just multiply x by 1 in the code. e.g. x x 1; and the error warning will go away.

Maybe my answer to this question will answer your question https secure.csse.uwa.edu.au run help2002?p np opt U344 hl arg0 Let me know.

ANONYMOUS wrote I mean a lot of the advice given on the forum is based off the project requirements and clarifications Chris made, so it really depends on which advice you are talking about. A rule of thumb for assumptions is If you make an assumpti...

ANONYMOUS wrote Seems good so far. Just make sure to delete the output.c file and the executable when you are done.

ANONYMOUS wrote Answered here https secure.csse.uwa.edu.au run help2002?p np opt U278 hl website

ANONYMOUS wrote This is a statement, so yes. pqr will be zero so it won't matter. sas will cause the error, since there are two identifiers followed after each other in a statement, which is invalid syntax.

ANONYMOUS wrote Hi sorry, you are right. I misread what he said. Thanks for letting everyone know.

This is invalid syntax. program A program is made up of zero or more program items. program-item A program item is either a statement or a function, a function can have zero or more identifiers. statement A statement is either an assignment or a pri...

ANONYMOUS wrote The file is temporary and will be deleted by your program. So, you can name it whatever you want (but make 110 sure the name doesn't and will not collide with other file names when run on other people's computers). However, the reaso...

ANONYMOUS wrote Write them to the file into their respective identifiers. E.g. arg0 is argv 2 assumption. I believe Chris said that you can assume the appropriate number of command line arguments are passed to the ml program https secure.csse.uwa....

ANONYMOUS wrote You can't pass "integers" to a function; the arguments are always doubles, so even if you pass 2, because the argument was defined to be a double, it will become 2.0. Every time you see a constant number, just put (double) in front of...

ANONYMOUS wrote Amitava needs to answer this one. From project specification "Your submission will be examined, compiled, and run on a contemporary Ubuntu Linux or macOS platform. Your project only needs to execute successfully on one of these platfo...

ANONYMOUS wrote Hi, in both cases, the variables would be considered global since they are not located inside of a function.

Hi Yuxuan You are allowed to make assumptions and submit them with your code submission. I believe the original intension was that all expressions will be valid, so you don't need to check them. Statements in a function should be 1 tab and everything ...

ANONYMOUS wrote Yea that's fine as long as you delete all the files you create. The only thing that needs to be a single file is the runml program itself.

https teaching.csse.uwa.edu.au units CITS2002 projects project1-syntax.php

No ml doesn't allow passing a function to a function. It is too complex for this project, and I don't believe it will be covered in the unit.

ANONYMOUS wrote Yes, the ml syntax allows it.

ANONYMOUS wrote Yes, otherwise if you have already done it Amitava said you can state the assumptions you made in a file. So, you can do either, just state what assumption you made.

ANONYMOUS wrote Best to ask Amitava.

ANONYMOUS wrote Yes

ANONYMOUS wrote No, because we are assuming expressions are valid and don't need to be checked.

ANONYMOUS wrote Best to ask Amitava.

ANONYMOUS wrote Best to ask Amitava.

If you want to be 100 sure you can ask Amitava. You can always do something with var to remove the warning. Literally just do var var 1 and the warning will go away.

ANONYMOUS wrote Tabs are a form of white space. More detail given here https secure.csse.uwa.edu.au run help2002?p np opt U351

Best to ask Amitava for clarification.

ANONYMOUS wrote Technically they're not considered "identifiers" just "variables". So, in other words, they're an exception to the rule. As stated in the project description "8.the variables arg0, arg1, and so on, provide access to the program's comm...

ANONYMOUS wrote It does apply to comments. He made the change to make sure the project isn't too hard. From Oxford English Dictionary "white space n. (a) Typography the blank areas of a page or other piece of printed matter, as margins, gutters betwe...

ANONYMOUS wrote Best to ask Amitava.

ANONYMOUS wrote You are missing something. You replace the identifiers (in the ml file) arg0, arg1, arg2, etc. By the command line arguments that are passed to run ml. e.g. . runml somefile.ml 1 2 3 means that in the ml file the parameters will be initi...

ANONYMOUS wrote If print appear outside a function in ml, then you put the print statements in main otherwise you'll get an error.

I believe so, they would be two separate identifiers, but they would count towards "unique" identifiers since they have the same name.

ANONYMOUS wrote Why can't the same identifier name be reused? After the function ends the program would believe it is seeing the identifier for the first time and so would initialize it to 0.

ANONYMOUS wrote Yes. Otherwise, there would be no way to differentiate between a normal variable and a command line argument.

ANONYMOUS wrote Just add return 0.0 to the end of your functions if they don't have a return statement.

ANONYMOUS wrote I believe Chris said either in the forum or the project sheet that all statements must start at the lefthand most side of the file unless it is a statement in a function. Not sure where a comment could appear (because technically comme...

It would. Or you can write an if statement in the c version of the ml file to change what is printed, then let c do the hard work. That would make the most logical sense. Since warnings can be errors and do something unintended. No guarantees about the...

Yes, I forgot there are no "if" statements in ml, because there are no "if" statements, it would run forever. So, don't worry about recursion. Can't see the point in testing an infinite loop.

ANONYMOUS wrote Hey guys, ml accepts whole numbers, there is no example in the ml file where there is a decimal point after a whole number, e.g. 2.0 would just appear as 2 in the ml file. I'm assuming as more decimal places are required they will be ...

The syntax of ml does seem to allow recursion, shouldn't be hard to implement (since you just copy the function call into C).

ANONYMOUS wrote Best to ask Amitava.

Best to ask Amitava.

Note there are no empty lines in ml, "empty lines" start with a .

ANONYMOUS wrote It would be illegal. The syntax of ml doesn't allow the printing of statements.

You wouldn't need to check mismatched brackets as Chris said expression checking isn't necessary. Yes, if 24.00, print as 24. if 24.5, print as 24.500000 Not sure but better to be safe than sorry and assume it can be as deep as it is in C.

I would say it works as it does in c, and would return 0, so the outer print would return 1.

Hi Trisha, Sorry for the delay. If no clarification is given, better to be safe than sorry and assume it is possible. This functionality is allowed within the ml syntax.

ANONYMOUS wrote Hi unfortunately because Chris is now on leave, I'm not sure if the website will be released.

ANONYMOUS wrote If no clarification is given, better to be safe than sorry and check the number of parameters.

Identifiers and functions shouldn't have the same name. Syntax of ml allows this. You should be able to just copy the function call into c and it would work.

You need to change the format string of printf so that you print the double without any decimal places. Answered here https secure.csse.uwa.edu.au run help2002?p np opt U245 hl integer I would say so. Some warning in C are straight up errors and res...

ANONYMOUS wrote Yes, that seems correct.

ANONYMOUS wrote Hi I don't believe empty lines are allowed in ml, all the sample files have no empty lines and instead use a comment to create an "empty" line.

I believe it is fine to return zero if a function doesn't have a return value. Amitava please respond to the second question.

ANONYMOUS wrote I think either is fine, but returning 0.0 is probably easier.

ANONYMOUS wrote Depends on whether the function returns a value or not. You could just always have the function return a double and just add return 0.0 to the end of the function if there is no return value.

ANONYMOUS wrote From your attachment your runml isn't correct. As many of the samples print, yet there is no output in your terminal.

ANONYMOUS wrote If the ml file prints then the correct output should appear in the terminal. The ml file should throw an error if there a syntax error in the ml file. Likewise the ml file should correctly run and not throw an error if there are no er...

Hi Anon, Amitava said the deadline is next week Friday.

You can do that if you want but I think the easiest way is to replace a with 0.0 if it doesn't match any identifier stored.

Hi Zexu, "7.variables do not need to be defined before being used in an expression, and are automatically initialised to the (real) value 0.0" "12. a function's parameters and any other identifiers used in a function body are local to that function, an...

Hi From my understanding, Chris said "appearing" so, you should only see at most 50 unique identifiers in a single ml file. So, in the case above b would count towards the total.

ANONYMOUS wrote Hi From my understanding, Chris said "appearing" so, you should only see at most 50 unique identifiers in a single ml file. So, in the case above b would count towards the total.

Actually sorry, I just realized made a mistake the datatype used should be doubles not floats because it has more precision (e.g. reduces rounding errors). So that way if you're multiplying dividing real numbers and showing 6 decimal plac...

ANONYMOUS wrote "4.only a single datatype is supported - real numbers, such as 2.71828" All parameters will be real numbers (doubles) as that is the only datatype supported.

functions

ANONYMOUS wrote Hi, There can be zero or more function in ml.

ANONYMOUS wrote Hi question is answered here https secure.csse.uwa.edu.au run help2002?p np opt U145

np. It is this bit "Otherwise, whitespace can (but doesn't need to) appear anywhere else" In other words, both ways of calling the function as you have shown above are correct. A function call can have white space but doesn't need to have white sp...

ANONYMOUS wrote I feel you are reading too deeply into that section of that paragraph. If you continue reading "The strategy is to first translate programs written in other languages, such as our ml, to C, to compile that translated C code using a st...

Hi Harrison Sorry for the delay, unfortunately, there's been sudden changes to the teaching staff, so I have to wait for the new unit coordinator to clarify these questions. Answered here https secure.csse.uwa.edu.au run help2002?p np opt U201 perr...

ANONYMOUS wrote Honestly it would be very hard to tell if a statement is meant to be in a function but it isn't. Since ml syntax allows statements to be inside or outside a function, there's no way of telling if they belong to a function if they aren...

There are no integers in the ml program, all the constants are real numbers, as that is the only datatype supported by ml. So, all the constant integer values in the ml program are actually floats. e.g. "2" is technically "2.0". If there are rounding...

ANONYMOUS wrote There are no guarantees what the last statement in a function will be, it could return, it could print, or it could be another statement (the syntax of ml allows this). So, relying on seeing a particular statement to know if the funct...

ANONYMOUS wrote You do not need to display the comments in the c file. Since the c file gets deleted anyway. So, when you come across a comment in ml you can just ignore it.

Ok let me try writing this out again, since half of my response got deleted. When you run your program like so . runml sample.ml runml (your project) will read the ml file given as the first parameter (in this case sample.ml), it will validate th...

For some reason it isn't appearing. The code is ". runml sample.ml"

The content in the code block is . runml sample.ml

ANONYMOUS wrote Hi anon, I'm not 100 sure what you are asking but when you run your program like so . runml sample.ml runml (your project) will read the ml file given as the first parameter (in this case sample.ml), it will validate the m...

Hi Both of those messages are fine, but in general the more descriptive the error message, the better.

Hi Josiah, The ml language only supports real numbers. So, an ml file wouldn't contain a string literal.

Hi Chenjun, When printed, numbers that are exact integers must be printed without any decimal places; other numbers must be printed with exactly 6 decimal places. Your program wouldn't need two datatypes, it would just need to change the format string ...

Hello anon, Judging by the Syntax of ml, I would say parenthesis are required for function calls.

ANONYMOUS wrote Hi anon, I believe your question in answered in these two posts https secure.csse.uwa.edu.au run help2002?p np opt U145 https secure.csse.uwa.edu.au run help2002?opt U132

Yes, that would break my cool idea. However, we can still fix it, just keep track of the quotes too. If we saw a quote ignore everything until we see another quote. Unfortunately, ml only supports real numbers, which makes me sad as this circumstance ...

Hi Guys, Sorry about the delays replying. Some questions about project requirements are really good so I need further clarification (from teaching staff) before I can respond (I don't want to make the project too hard). So, for now if you are unsure o...

I should also mention you'd likely need to recursively "check" functions, e.g. If you're checking the parameters and encounter another function, start checking the new function. But like I said I'm not sure if it is necessary.

I'm not sure if it is necessary but it does sound like fun (if you're me anyway). You could check the number of arguments by counting the number of commas and the number of open brackets without a closing bracket. If number of open brackets is 1, then...

Hey Anon your question is answered here https secure.csse.uwa.edu.au run help2002?p np opt U172

Hi Functions don't always have a return statement (see sample05.ml). Your other question in this post https secure.csse.uwa.edu.au run help2002?p np opt U145

Hello, I think your question is answered by this post https secure.csse.uwa.edu.au run help2002?p np opt U145

Hey Guys, sadly I am not the prof, but I believe your questions are answered by the following posts 1. https secure.csse.uwa.edu.au run help2002?p np opt U145 2.https secure.csse.uwa.edu.au run help2002?opt U132

Hi, your question is answered here https secure.csse.uwa.edu.au run help2002?p np opt U145

Hi, your question is answered here https secure.csse.uwa.edu.au run help2002?p np opt U151

Hi, the way I remember it is that refers to a pointer if a datatype comes before it e.g. int . If there is no type beforehand, then is the dereference operation. e.g. int p , declares a pointer to an int. p refers to...

This forum post may answer your question https secure.csse.uwa.edu.au run help2002?p np opt U143

Hi unfortunately I am not Chris, but this forum post may answer your question post (https secure.csse.uwa.edu.au run help2002?p np opt U151)

ANONYMOUS wrote You're right. I think there is a typo in the answer. None of the options are correct. However, there is one option that is very close to the correct answer. Can you see which one it is?

ANONYMOUS wrote One place to the left means index - 1 . e.g. If an integer is at index 3 it will be at index 2 after the code runs. Likewise, if an integer is at index 1, then after the code runs it will be at index 0. I hope that makes sense.

Hi Guys, I am just reminding you to always keep up to date with the lectures, workshops and labs . If you don't you will struggle with this unit as there is a lot of content. Do not skip the lab exercises they are assessable and build up the fou...

Hey Jinyoung If I remember correctly floats are 4 bytes and doubles are 8 bytes (hence the name double) but Chris may need to clarify. An integer value must be at least 2 bytes (or 16 bits) but it is usually 4 bytes (32 bits). It's a bit confusing ...