For give my poor English, this question really confused me:

You are asked to write a C11 function to locate and print all potential trojan- horse programs found via a user’s “PATH” environment variable. The C11 function should have the prototype: int find potential trojans(char *testpath); If there are 3 executable programs named “ls” and 2 named “cp” that can be found via a “PATH” environment variable, then the function will print the full pathnames of all 5 programs, and return the integer 5 to indicate the number of suspicious programs found.

Does that mean: if there are EXACTLY 3 executable programs named “ls” and 2 named “cp” the function returns 5, all other situations, it returns 0 or something?

OR, if there are 1 lses, and 1 cps, it will return 2 if there are 2 lses, and 1 cps, it will return 3 if there is no lese, no cps, it return 0?

ANONYMOUS wrote:

For give my poor English, this question really confused me:

All good, this question isn't worded well.

You are asked to write a C11 function to locate and print all potential trojan- horse programs found via a user’s “PATH” environment variable. The C11 function should have the prototype: int find potential trojans(char *testpath);

This is the program you are meant to make.

If there are 3 executable programs named “ls” and 2 named “cp” that can be found via a “PATH” environment variable, then the function will >print the full pathnames of all 5 programs, and return the integer 5 to indicate the number of suspicious programs found.

This is an example of how your function would work.

OR, if there are 1 lses, and 1 cps, it will return 2 if there are 2 lses, and 1 cps, it will return 3 if there is no lese, no cps, it return 0?

Yes.

"Joshua Noble" [email protected] wrote:

This is the program you are meant to make.

I meant to say function not program.

will there be any writing code questions?