> ANONYMOUS wrote: > > > Hello, I am reposting my question as it seems my question has been missed. Could someone please clarify or help with my understanding please? The question is below > > > > > > Hi all! I'm currently on Past Exam 2021 Question 5. I'm wondering if for > > > > """ > > A computer system employing 32-bit addresses implements virtual memory > > using a two-level page table. > > The right-most 10 bits of each virtual address are used to specify the required > > offset within a page. The left-most 8 bits are used to index the primary (or > > root) page table, and the remaining ‘middle’ 14 bits are used for the secondary > > page tables. > > (a) What is the page size in this machine? > > (b) What is the size of the primary page table? > > (c) What is the number of secondary page tables? > > (d) Explain why it is sufficient to keep only the primary page table in the > > RAM. > > """ > > > > > > (b) What is the size of the primary page table? > > Does it want the amount of entries which would be 2^8 = 256 entries or would it be 2^8 x 4 bytes = 1024 bytes > > > > (c) What is the number of secondary page tables? > > Would this just be 256 since each entry in primary would mean 1 secondary page? > > > > Thanks for the help! > page size is 2^10 > primary page table size is 2^8 > There are 2^14 secondary page tables, each entry of the primary page table holds the starting address of a secondary page table. > One can bring the secondary page tables on demand (the secondary page tables are paged)