Would this be with using the memory management tools like malloc to create arrays in heap instead of stack and caching variables that get used repeatedly?

Hi, as I understand the principle of referential locality it means that memory references are typically close together. The question asks "With reference to two distinct examples, explain The Principle of Referential Locality, and explain how an operat...

before receiving input the project specifications say "We have a computer whose RAM is an array of size 16. It is an array of pointers. There are 8 page frames in the RAM, each consisting of two contiguous locations in the array. Hence, the page size o...

page process id,page num,time before input RAM pages 0,0,0 , 0,1,0 , 0,2,0 , 0,3,0 , 1,4,0 , 1,5,0 , 1,6,0 , 1,7,0 DISC pages 0,99,0 , 0,99,0 , 0,99,0 , 0,99,0 , 1,99,0 , 1,99,0 , 1,99,0 , 1,99,0 , 2,99,0 , 2,99,0 , 2,99,0 , 2,99,0 , 3,99,0 , 3...

the way I understand the project is that it starts loaded in with the first 2 processes (page numbers 0-7) but because there are 16 pages in disc there is also a copy of process 0 and 1 in disc so instruction 0 bring in least recently used page into R...

so if the RAM has page numbers 0-7 from processes 0 and 1 all initially time step 0, and the disc has processes 2-3, and we receive the instruction '0' there is nothing to move in from the disc as all of process 0 is in RAM. We need to evict the first...

yes that's the page table, with corrected indexes it looks like this process 0 0,1,2,3 process 1; 4,5,6,7 process 2 99,99,99,99 process 3 99,99,99,99 process 0 and 1 are loaded into ram with values 0-7 but now there is a new issue with instruction '0' '...

Ok that makes sense, RAM and DISC are the values of the page table of the currently loaded processes so RAM 0,1,2,3,4,5,6,7 DISK 99,99,99,99,99,99,99,99 instruction 3 RAM 0- 99 (evicting process 1 (value 0) and replacing with process 3 (value 99)),1,2,...

Hi, if we load the page frames in sorted by page num the memory looks like this process 1 0,1,2,3 process 2 4,5,6,7 process 3 99,99,99,99 process 4 99,99,99,99 RAM 0,1,2,3,4,5,6,7 DISK 99,99,99,99,99,99,99 but if we get the instruction '3' there is no...

i'm seeking a 2nd project partner, my email is 24312743