It's UWAweek 45 (2nd semester, 2nd exam week)

help2002

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 UWA week 42 (2nd semester, week 12) ↓
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helpful
8:17pm Mon 14th Oct, ANONYMOUS

ANONYMOUS wrote:
> Hi, no this this should not be the case. Note that a process will always replace one of its own pages if the RAM is full and there is one available to replace (as local replacement is prioritised over global). > > As a result of this, once 1 page of each process is in the RAM and the RAM is full each process will have a consistent number of pages. In this case you would end up with 3 process 0, 2 process 1 pages, 2 process 2 pages and 1 process 3 page. > > You are correct that you can update the last access time of the page 0 process 0 after the 5th 0 though.
Noted, I've made the changes. Could you verify if this should be the correct output? Thanks! in.txt 0 0 0 0 0 1 1 2 2 3 3 2 2 1 1 out.txt 0, 99, 2, 3 99, 99, 4, 5 99, 99, 6, 7 99, 1, 99, 99 RAM Contents: 0,0,4; 0,0,4; 3,1,10; 3,1,10; 0,2,2; 0,2,2; 0,3,3; 0,3,3; 1,2,13; 1,2,13; 1,3,14; 1,3,14; 2,2,11; 2,2,11; 2,3,12; 2,3,12

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